I have a series of questions similar to the following. I want to make sure I do this correct before I do the others. I am in need of a hint.
Given molarity of 6M NaOH with d=1.4g/mL, calculate, percent, mole fraction, and molality.
So in the above question, I have the molarity, but how am I supposed to get liters of solution?
I figured it was 6M per 1L of water, but then what am I supposed to do with the density? Is that the density of the water with the NaOH?
Then in a sub part it gives me the mole fraction as 0.1 with a density of 1.3g/mL. Why does the question give me that number? Is it possible to figure out percent, molality, and molarity based on mole fraction?
Thanks for you help.