Are phenoquinone and benzoquinone the same thing? When I searched for the colour of benzoquinone I found that it's yellow. But when I searched oxidation of phenol in air. It states that it turns pink/red due to formation of phenoquinone. Also when aniline is oxidised with $\ce{K2Cr2O7}$ quinone is formed (perhaps it is aniline black). Is it the same compound everywhere?
1 Answer
Benzoquinone($\ce{C6H4O2}$) is a quinone with a single benzene ring. There are two types of benzoquinone:
- 1,4-Benzoquinone also called p-benzoquinone. More common type of benzoquinone. It is the main product of oxidation of phenol.
- 1,2-Benzoquinone also called o-benzoquinone. Less common type of benzoquinone.
Phenoquinone is a crystalline complex made of one quinone molecule and 2 phenol molecules. It is most likely formed from the polymerization of benzoquinone, hence the color change from yellow to reddish pink. See the mechanism below, taken from this answer:
It is formulated as $\ce{C6H4O2.2(C6H5OH)}$. See: http://scripts.iucr.org/cgi-bin/paper?S0567740868002451
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$\begingroup$ Such adducts are not hydrogen bound, but charge transfer complexes. $\endgroup$– MithoronJun 28, 2020 at 17:29
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$\begingroup$ @Mithoron From ref 4 of my answer: "Different molecules in each complex are connected by hydrogen bond between the hydroxyl bond and carbonyl bond [...] In phenoquinone, one quinone molecule is placed between two phenol molecules to form a short complex chain. In spite of difference of complex chain, no significant difference was observed between complex due to short interatomic distance". I changed the "adduct" to "crystalline complex" but there is indeed a hydrogen bond between them. $\endgroup$ Jun 28, 2020 at 17:50
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$\begingroup$ What "ref 4"? I've seen this misconception earlier and it's quite obvious. $\endgroup$– MithoronJun 28, 2020 at 18:02
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1$\begingroup$ While then sure can be (even should be!) h-bonds between individual phenol-quinone complexes, color change cannot be attributed to them, but to change transfer between the rings stacked one over another. $\endgroup$– MithoronJun 28, 2020 at 18:10