# How do ions conduct electricity? [closed]

I mean to ask what do ions actually do while conducting electricity?

Do they simply take up the electrons and transport it? If it is so, I do not understand how anions can take up more electrons if they are already negatively charged? And if cations take up the electrons, won't they be converted to their elemental forms? Then they no longer remain an ion, so how will they keep conducting? Or is it a completely different mechanism?

• This forum is probably more appropriate for the questin: physics.stackexchange.com But short answer - the movement of a charge (be it an ion or an electron) is electricity. – Stanislav Bashkyrtsev Jun 22 '20 at 7:19
• Forget electrons. Ions themselves are already charged, and the motion of charged particles is electric current. – Ivan Neretin Jun 22 '20 at 7:31
• So this question should be posted in Physics Stack exchange?? – Black Fire Jun 22 '20 at 8:20
• I recommend looking up the meaning of the various terms you are mentioning, for instance ion, electron, conductor, current. The Wikipedia or an online dictionary may be a useful resource. – Buck Thorn Jun 22 '20 at 8:48
• Ok so simply the movement of the ions is the conduction of electricity? It may or may not involve the transfer of electrons, right? – Black Fire Jun 22 '20 at 9:19

There are never neutral atoms in pure $$\ce{NaCl}$$ or in its solutions. The pure $$\ce{NaCl}$$ crystal is made of piles of ions $$\ce{Na^+}$$ and $$\ce{Cl-}$$. When $$\ce{NaCl}$$ is dissolved into water, the ions $$\ce{Na^+}$$ and $$\ce{Cl-}$$ are separated. They become independent and can move in water. If you dip in this solution two conducting pieces bound to the poles of a battery, a positive pole (anode) and a negative pole (cathode) are created in the solution. The positive pole (anode) attracts the negative ions (anions) like $$\ce{Cl^-}$$ : they slowly migrate in the solution up to the anode, and when they touch the anode, they lose their charge and create a free electron which enters the anode and the external circuit. The anions become neutral atoms $$\ce{Cl}$$. So the anions do not take up electrons as you say. They already have electrons in excess, before the beginning of the electrolysis.
To be correct I should also mention that positive ions like $$\ce{Na^+}$$ are also migrating in the solution, as they are attracted by the negative pole (cathode). So in the solution, there is one currant of positive ions moving to the negative electrode. And there is also a currant of negative ions moving to the positive electrode. As a result the solution remains neutral, without any positive or negative electric charges in excess.