There is a similar question already on StackExchange which was not satisfactorily answered. So I am asking it again. I am unable to find this information in any book.
Link to the other question: Acidity of aluminium trihalides
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2$\begingroup$ What question do you refer to? What is unsatisfactory about the existing answer? Why the name of the scientist isn't capitalized, but the name of a chemical compound is? Also, please familiarize yourself with the homework policy. $\endgroup$– andselisk ♦Commented Jun 21, 2020 at 18:39
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$\begingroup$ I have provided the link @adnselisk $\endgroup$– user137644Commented Jun 21, 2020 at 18:51
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2$\begingroup$ Does this answer your question? Acidity of aluminium trihalides $\endgroup$– MithoronCommented Jun 22, 2020 at 14:42
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$\begingroup$ I just wanted an answer and so asked it again...as no one answered the previous one properly... $\endgroup$– user137644Commented Jun 22, 2020 at 14:47
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1 Answer
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According to Ref.1: The order of Lewis acidity of gaseous halides of aluminum is established to be $\ce{AlF3(g) < AlCl3(g) < AlBr3(g) \approx AlI3(g)}$. The order of Lewis acidity of molecular and solid group 13 halides is $\ce{AlX3(g) > GaX3(g) > InX3(g)}$ (where $\ce{X = F, Cl, Br, I}$).
References:
- Thoralf Krahl, Erhard Kemnitz, “The very strong solid Lewis acids aluminium chlorofluoride (ACF) and bromofluoride (ABF)—Synthesis, structure, and Lewis acidity,” Journal of Fluorine Chemistry 2006, 127(6), 663-678 (https://doi.org/10.1016/j.jfluchem.2006.02.015).
answered Jun 23, 2020 at 7:29
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$\begingroup$ Does the solid state also have the same order? $\endgroup$ Commented Jun 23, 2020 at 7:35
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$\begingroup$ Can't say without any data. Keep in mind that at solid state, these halides tend to make dimers, trimers, etc., thus different than gaseous phase. $\endgroup$ Commented Jun 23, 2020 at 7:38
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$\begingroup$ Ok....does the same order apply for the catalytic action during Friedel Crafts reaction? $\endgroup$ Commented Jun 23, 2020 at 7:41
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$\begingroup$ Should be. But most common one is $\ce{AlCl3}$ due to its covalent nature in non-polar solvents. $\endgroup$ Commented Jun 23, 2020 at 7:57