# Gibbs free energy where T, V, and P change simultaneously

So $$\Delta G = \Delta H - T\Delta S - S\Delta T$$.

Is there a way to express $$\Delta G$$ for a process where T, V, and P change simultaneously only in terms of the initial and final T, V, P? Assume this process is for an ideal gas.

Since $$G$$ is a state function I can calculate it separately for an isothermal process and an isochoric process, but in that case $$\Delta G$$ for the isochoric process has dependence on the entropy of one of the states.

Your original equation is incorrect. It should read $$\Delta G=\Delta H -\Delta (TS)$$, and $$\Delta (TS)\neq T\Delta S+S\Delta T$$ unless the changes are infinitesimal.
That said, for an ideal gas, irrespective of path, $$\Delta S=S_f-S_i=C_p\ln{(T_f/T_i)}-R\ln{(P_f/P_i)}=C_v\ln{(T_f/T_i)}+R\ln{(V_f/V_i)}$$and$$\Delta H=C_p(T_f-T_i)$$So, $$\Delta G=G_f-G_i=C_p\Delta T-\frac{(T_f+T_i)}{2}\Delta S-\frac{(S_f+S_i)}{2}\Delta T$$Clearly the 3rd term on the rhs depends on either $$S_i$$, $$S_f$$, or both, so $$\Delta G$$ depends on these. It then all comes down to how you assign your reference state values for G, H, and S, such that $$G_{ref}=H_{ref}-T_{ref}S_{ref}$$.