0
$\begingroup$

Let's say we have some neutral molecule A and its protonated form, A+. The pKa of molecule A is known, but we do not know the pKa of molecule A+. Can the pKa of molecule A+ be determined only knowing the pka of molecule A? For example, is there an expression that relates the pKa values of arginine together? (For reference, arginine's pKa values are are 2, 9, 12.5.)

The context of this question lies in trying to understand how the protonation state of molecule A+ will change in an inhomogeneous environment (for example, a lipid bilayer). The pKa of molecule A+ is estimated to change +2 pK units in the bilayer relative to in aqueous solution. The pKa of molecule A is known to be 7.09, but the pKa of molecule A+ is not known. How can any change in protonation state of molecule A+ be predicted given only this information?

Note that this question is NOT asking the protonation state of a molecule if we know THAT molecule's pKa and if we know how ITS pKa changes (for example, as was asked previously).

$\endgroup$
  • 1
    $\begingroup$ No, these values are quite independent of each other. $\endgroup$ – Ivan Neretin May 1 at 7:48
  • $\begingroup$ @IvanNeretin, I see. Does that mean the second question also becomes moot? Is there any information that can be drawn from A+ and its predicted change in pKa? $\endgroup$ – halcyon May 1 at 7:57
  • $\begingroup$ Yes, pretty much so. These are independent species. Sure, the pKa of second protonation must be higher than the first (otherwise why would it be second?), but that's all about it. $\endgroup$ – Ivan Neretin May 1 at 11:24
  • $\begingroup$ For clarification: Do you mean A and A+ are at the same position of the molecule (like acetate vs. acetic acid vs H3CCOOH2+ (the 2 oxygens protonated) or the situation at several functional groups within a molecule, like in your arginine example above? $\endgroup$ – imalipusram May 1 at 13:03
  • $\begingroup$ @imalipusram, My molecule has just one expected protonation state, so one position and not like the arginine example. $\endgroup$ – halcyon May 1 at 18:05

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.