1
$\begingroup$
  1. $\ce{CH3CH=CHCO2CH3}$
  2. $\ce{CH3COOCH=CHCH3}$

$\pu{2950 cm-1}, \ \pu{2870 cm-1}, \ \pu{1740 cm-1}$ are the observed peaks.

No peaks observed $\pu{1700-1500 cm-1}$.

The formula of the molecule is $\ce{C5H8O2}$.

My pre-answer is the first option. Because $\pu{1500-1700 cm-1}$ includes unsaturated carbons.

$\endgroup$
6
  • 1
    $\begingroup$ Does not correspond to the literature spectrum for 1 chemicalbook.com/SpectrumEN_623-43-8_IR1.htm $\endgroup$ – Waylander Apr 20 '20 at 12:58
  • $\begingroup$ So, the first one is wrong. And, the answer is 2. Nothing else?@Waylander $\endgroup$ – Yeliz Gülsün Apr 20 '20 at 13:59
  • $\begingroup$ I'm not a fan of IR as a diagnostic for structural determination, and have not used it much for the last 30 years. NMR is much stronger. $\endgroup$ – Waylander Apr 20 '20 at 14:28
  • $\begingroup$ Thanks for your comments. My professor is awaiting replies from me.@Waylander $\endgroup$ – Yeliz Gülsün Apr 20 '20 at 14:49
  • $\begingroup$ 1740 is a bit low for the carbonyl of a vinyl ester according to my old copy of Williams & Fleming but it could be that signal $\endgroup$ – Waylander Apr 20 '20 at 15:08

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.