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Having to retake an introductory chemistry course has gotten me thinking. Covalent bonding is where electrons are shared between two atoms that both want more electrons.

Let us take $\ce{O2}$ as an example.

enter image description here

The red and purple oxygen atoms share 2 electrons. This means that they now both have 8. Fantastic!

However, electrons do not sit around statically but rather buzz around randomly. If the electron moves around, then on average having 4 electrons between 2 atoms means 2 electrons each. This means no one is any better off than from when we started.

My question is, seeing as the electron sharing would actually mean that on average each atom still only has 6 electrons, how can they become stable in this covalent bond?

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  • $\begingroup$ One thing to keep in mind is that a lone oxygen atom does not want 10 electrons (including the 2 $1s$) around it. As a doubly-negative ion it will rapidly autoionize. But, it does prefer to share a few electrons with another oxygen atom (that shares a few with it) as part of them negotiating to make a molecule. $\endgroup$ – Jon Custer Mar 31 at 14:14
  • $\begingroup$ chemistry.stackexchange.com/questions/710/… $\endgroup$ – Mithoron Mar 31 at 14:57
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    $\begingroup$ What answer would you want really? It's clear that "having 8 electrons" is a dumb rule of thumb for kids, especially in this case - dioxygen is a biradical and its bonding looks quite differently then you write, but on your level of learning of chemistry... let's just say that "electrons do not sit around statically but rather buzz around" isn't useful thinking there, some would even think it completely incorrect; not me but it's utterly useless when actual bonding is concerned. $\endgroup$ – Mithoron Mar 31 at 15:09
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You seem to forget that electrons have spins. And that there are two possibilities for the spin : up or down. No other possibilities exist. Now electrons have the tendency to make pairs with one spin up and on down. Sorry for the image, but it looks as if spins up and down represent two different sexes. And that the electron have the tendency to make "couples" of "up" and "down" together, as in the traditional way of being together. On the average, there exist the same amount of electrons "up" and of electrons "down".

Let's take H atoms. Half to the H atoms have spins up, and half down. If you produce somewhere a lot of free H atoms, they will collide. When they have the same spin, nothing happen after the collision. When they have different spins, they will join and stay together, make a covalent bond, which makes a H2 molecule, after the collision. After a while all H atoms are groups in H2 molecules

In the next atom, Helium, there are two electrons on the first layer. They are of opposite spins and Helium will not join with any other atom, and not produce any molecule.

For heavier atoms, form Li to Ne, there is enough room for 8 electrons. The first four have the same spin. The next four have the opposite spin. Hopefully you may understand your self that Li makes LiH, Be makes BeH2, etc. But Oxygen has 6 electrons, 4 of a given spin and 2 of the opposite spin. In Oxygen, there are two doublets which cannot form covalent bonds. Only 2 can do it.

I will not develop this theory too long. You may do it your self. It is not too difficult to do it.

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