# Activation energy vs temperature [closed]

We know that activation energy is independent of temperature. But during the dehydration of alcohol or any reaction, activation reaction can be increased by following the thermodynamically controlled product, which is favourable at high temperature. So how is it possible?

• The thermodynamically controlled product is irrelevant to activation energy. Feb 15 '20 at 7:31

Activation energy is an experimental result, obtained from the slope of the log of the rate constant vs $$1/T$$. It is usually determined over a rather small domain of temperature, much less than $$100\ \mathrm{^\circ C}$$. Who knows whether this slope is dependent on $$T$$, if it could be measured between, say, $$10\ \mathrm K$$ and $$1000\ \mathrm K$$?