What are the products formed when $\ce{Sn(NO3)2}$ is subjected to high temperatures?
I searched over the internet but I didn't get any satisfactory answer.
Chemistry Stack Exchange is a question and answer site for scientists, academics, teachers, and students in the field of chemistry. It only takes a minute to sign up.
Sign up to join this communityWhat are the products formed when $\ce{Sn(NO3)2}$ is subjected to high temperatures?
I searched over the internet but I didn't get any satisfactory answer.
No wonder you cannot find any literature on $\ce{Sn(NO3)2}$, because I don't think it exists in solid form. This is supported by the fact that I even can't find its CAS number online. This book (Ref.1) and relevant paper (Ref.2) support my suggestion, both of which state that:
Attempts to prepare a covalently bound tin(II) nitrate, by the reaction of tin(IV) tetranitrate with anhydrous nitric oxide, have produced only a white solid solid of formula $\ce{SnN2O6}$, which gives a tin(IV) Mössbauer resonance ($\delta = \pu{0.29 mm\:s-1}$, $\Delta = \pu{0.96 mm\:s-1}$)...
Nonetheless, a study on thermal decomposition of metal nitrates (Ref.3) states that:
Due to a back-donation of electronic cloud from the nitrate to an unfilled $\mathrm{d}$-orbital of transition and noble metals, their nitrates generally exhibited lower decomposition temperatures ($T_d \lt \pu{700 K}$) than those of the base metals ($\gt \pu{850 K}$).
They suggest those metal nitrates with lower decomposition temperatures decompose to corresponding oxides together with $\ce{NO2}$ and $\ce{O2}$. Thus, it is safe to assume that if $\ce{Sn(NO3)2}$ exists, it would decompose as following reaction suggest:
$$\ce{2 Sn(NO3)2 (s) + heat -> 2 SnO (s) + 4 NO2 (g) + O2 (g)}$$
However, keep in mind that this is pure speculation.
References: