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We are told that L-Glucose is an enantiomer of D-Glucose, which would mean that they are mirror images of each other. But then we're also told that the L and D forms is determined by the spacial relationship to glyceraldehyde. enter image description here

Which of the structure is correct? Are they the same?

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    $\begingroup$ Strictly on the left there is not a projection. It is a projection like every other structural formula $\endgroup$ – Alchimista Jan 5 at 8:47
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It looks to me like the left one is just wrong. It looks like who made the image took D-glucose and just flipped the 5-OH.

The result? The molecule at left is not glucose, but L-Idose!

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They are the same If you draw all bonds of the left diagram and rotate the first sigma bond containing the aldehyde group, the right diagram will pop out The conventional Fischer protection is the right one. The left one seems to be a bit condensed and needs to be expanded

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