-1
$\begingroup$

I've been scrolling through a chemistry past question but when I came across this I tried to solve it but it keeps confusing me

Improve this question
$\endgroup$
1
  • 1
    $\begingroup$ Please write your question in the Body box. Your question should be clear even without the title. (Especially, do not write your whole question in the title and then put “title says it all” in the body.) $\endgroup$
    – user7951
    Jan 2, 2020 at 19:15

1 Answer 1

Reset to default
1
$\begingroup$

$\ce{CaCO3}$ is not soluble in water. Both $\ce{KCl}$ and $\ce{NH4Cl}$ are soluble in water. When heated $\ce{NH4Cl}$ sublimes at 335 °C. At this temperature, $\ce{CaCO3}$ and $\ce{KCl}$ are not modified. $\ce{CaCO3}$ is decomposed in $\ce{CaO}$ and $\ce{CO2}$ at 825 °C.

Improve this answer
$\endgroup$

Not the answer you're looking for? Browse other questions tagged or ask your own question.