1
$\begingroup$

What will be the major product of the reaction? I guess that rearrangement will take place and give 5-bromo-5-methylhex-2-ene as a product, but I'm completely not sure

$\endgroup$
  • 1
    $\begingroup$ Why do you think this will be the product? $\endgroup$ – Waylander Dec 14 '19 at 13:19
-2
$\begingroup$

In this reaction if peroxide is not present then reaction follows markovnikov addition in which carbonation is formed as intermediate. By stability due to resonance and 2° carbonation 5-methylhexa-1-ene cation with C+ at 3 is formed. Hence 3-bromo-5-methylhexa-1-ene is formed as product.

$\endgroup$

Not the answer you're looking for? Browse other questions tagged or ask your own question.