If one were to take $\pu{1 mol}$ of pure liquid Calcium Chloride (at $\pu{600 ^\circ C}$) and bombard it with $\pu{7.65 \times 10^{14} Ci}$ ($\pu{2.83 \times 10^25 particles}$) of x-rays ($\pu{75 keV}$), how the calcium chloride become chemically altered in anyway? Would the radiation cause the calcium and/or chloride ions to further ionize into a form that would not bond with the other ions?

I ask this because my purpose requires that the liquid $\ce{CaCl2}$ (not aqueous) would be able to keep the calcium and chlorine from precipitating out of the liquid.

  • 2
    $\begingroup$ What's Cu?$\mathstrut$ $\endgroup$ Nov 15, 2019 at 5:16
  • $\begingroup$ @ivan neretin Cu is the symbol for Curies in this case. 1 Curie is equal to around 3.7 * 10^10 x-rays per second. $\endgroup$
    – James Li
    Nov 15, 2019 at 12:08
  • 2
    $\begingroup$ I thought Curie is Ci, but what do I know. Whatever. Well, then in effect your sample is sitting near the center of a decent nuclear explosion, so its temperature, phase state, shape, chemical composition, and pretty much everything else about it are rather irrelevant. A rapidly expanding cloud of hot plasma does not remember what it was before. $\endgroup$ Nov 15, 2019 at 12:19
  • $\begingroup$ @IvanNeretin So effectively it will just become plasma? $\endgroup$
    – James Li
    Nov 15, 2019 at 12:46
  • $\begingroup$ Yes, many times over. $\endgroup$ Nov 15, 2019 at 13:27


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