# X-ray bombardment of CaCl2 and its resultant chemical changes

If one were to take $$\pu{1 mol}$$ of pure liquid Calcium Chloride (at $$\pu{600 ^\circ C}$$) and bombard it with $$\pu{7.65 \times 10^{14} Ci}$$ ($$\pu{2.83 \times 10^25 particles}$$) of x-rays ($$\pu{75 keV}$$), how the calcium chloride become chemically altered in anyway? Would the radiation cause the calcium and/or chloride ions to further ionize into a form that would not bond with the other ions?

I ask this because my purpose requires that the liquid $$\ce{CaCl2}$$ (not aqueous) would be able to keep the calcium and chlorine from precipitating out of the liquid.

• What's Cu?$\mathstrut$ – Ivan Neretin Nov 15 at 5:16
• @ivan neretin Cu is the symbol for Curies in this case. 1 Curie is equal to around 3.7 * 10^10 x-rays per second. – James Li Nov 15 at 12:08
• I thought Curie is Ci, but what do I know. Whatever. Well, then in effect your sample is sitting near the center of a decent nuclear explosion, so its temperature, phase state, shape, chemical composition, and pretty much everything else about it are rather irrelevant. A rapidly expanding cloud of hot plasma does not remember what it was before. – Ivan Neretin Nov 15 at 12:19
• @IvanNeretin So effectively it will just become plasma? – James Li Nov 15 at 12:46
• Yes, many times over. – Ivan Neretin Nov 15 at 13:27