Why London Force is greater than dipole-dipole interactions in Alkyl Halides?

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As we know that most of the time London force is weaker than other forces. Then why in this case it's not so?

According to me, due to high charge separation (in C & X) the dipole-dipole interaction must me stronger than the London force which depends more on the surface area of molecules.

Source:Leroy G.Wade Organic chemistry

  • $\begingroup$ That depends on halide, for bromides and iodides textbook is totally right. For chlorides and fluorides that somewhat depends, $\endgroup$ – Mithoron Nov 9 '19 at 17:08
  • $\begingroup$ @scientist omega please refer ro this chemgapedia.de/vsengine/vlu/vsc/en/ch/12/oc/vlu_organik/… $\endgroup$ – Hercules Nov 9 '19 at 17:22
  • $\begingroup$ Actually size of halogen is so big that it kind of shields C atoms which makes it harder for dipole dipole interaction.Plus large surface area increases London force. $\endgroup$ – Hercules Nov 9 '19 at 17:26

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