I'm having a bit of trouble with this question:
Which has a higher $\mathrm{pH}$ value, $\pu{0.001 M}$ $\ce{HCl}$ or $\pu{0.1 M}$ $\ce{CH3COOH}$ $(K_\mathrm{a} = \pu{1.8E-5})?$
I have calculated that for the $\ce{HCl}$ solution (since it's a strong acid) the $[\ce{H3O+}] = \pu{0.001 M}.$
Then, for the $\ce{CH3COOH}$ solution I got $[\ce{H3O+}] = \pu{1.33E-3 M}$ (by solving a quadratic equation).
Since the $\ce{CH3COOH}$ has a higher concentration of hydronium ions, doesn't this mean that it will have a lower $\mathrm{pH}$ than the other solution? I'm confused because the answer says it's the other way around.