I'm trying to understand how to predict ground state term symbol of atoms.
After finding the biggest S, why the biggest L will be $L = |M_L|$, where $M_L = \sum m_l$? I know this rule works to predict the total L, but it doesn't make sense to me that it will give the biggest L, to me it seems like this is the minimum L.
For example, the nitrogen atom has three electrons in 2p.
Following the first rule, the spin $S$ of the ground state will be the maximum possible, which is S = 3/2.
The second rule, according to some books is to maximize $M_L$, in the case of Nitrogen, according to Pauli principle, since all the spins are up, we can only get $M_L = 0$.
Now, all material I read says that L of the ground state will be the maximum one, so L = $|M_L|$, but if we expand the Clebsch-Gordan coefficients of the three states: $|1 \,\,\,\, 0> |1 -1> |1 \,\,\,\, 1>$ we get the possibility of L = 3,2,1 and 0, so why is L = 0 the maximum possible value?
There is an amazing answer to this here, but he doesn't explain why he cuts out the the terms with bigger L.