# How does the splitting in this molecule take place?

Consider the following molecule and data:

\begin{align} \mathrm{H_a} &= \pu{1.0 ppm} &\quad J_\mathrm{ab} &= \pu{5.0 Hz}\\ \mathrm{H_b} &= \pu{3.0 ppm} &\quad J_\mathrm{bc} &= \pu{8.0 Hz}\\ \mathrm{H_c} &= \pu{6.0 ppm} &\quad J_\mathrm{ac} &= \pu{1.0 Hz}\\ \end{align}

Draw a splitting diagram for $$\mathrm{H_b}.$$ $$(\pu{1 box} = \pu{1 Hz})$$

Tried to draw the splitting diagram and ended up with this diagram:

I am also stuck as to how to draw the spectrum of the whole molecule as I feel $$\mathrm{H_a}$$ would be triplet of triplet. Am I on the right track and how to draw the sketch of the spectrum?

• You missed a split. The central peak must also split on the last coupling. – Jan Oct 15 '19 at 8:28

According to given data, you may consider expected peak patterns are not complicated such as $$\mathrm{ABX}$$ or $$\mathrm{A_2B}$$ patterns (more reading look here. This is simply a $$\mathrm{A_2X}$$ pattern ($$\delta_X = \pu{6 ppm}$$ and $$\delta_A = \pu{1 ppm}$$ without geminal coupling of two $$\ce{H_b}$$ protons), and hence, peak is a $$dt$$ for $$\ce{H_b}$$ as depicted below with relative heights of the peaks:
Similarly, $$\ce{H_c}$$ is also a $$dt$$ resonance with $$J = 1 \text{ & } \pu{8 Hz}$$ and $$\ce{H_a}$$ is a $$tt$$ with $$J = 1 \text{ & } \pu{5 Hz}$$. OP should able to figure out the intensities of relevant peaks.