I was doing some questions based on dipole moment ortho,met and para compounds. I was not able to understand why dipole moment for \ce{C6H4NH2NO2} increases from ortho to para Because i think \ce{NH2} is more electronegative than \ce{C=C} in benzene ring hence dipole moment will be towards \ce{NH2} so it should decrease from ortho to para because most of it will be cancelled by \ce{NO2}. Any help will be appreciated.

  • $\begingroup$ Thanks to the mesomeric effect, NH2 is a donating group here. $\endgroup$ – Ivan Neretin Aug 28 at 8:02

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