I just learned that in $S_N2$ reaction there is an inversion of configuration. I thought that it is a change of $R$ to $S$ and vice-versa. But that is wrong as mentioned in this answer.

While I was referring to more sources I saw this.

enter image description here

Here it is mentioned that $S$ to changes to $R$. Shouldn't that be wrong as absolute configurations do not change?

EDIT: I solved a few problems and I think that $R$ to $S$ (and vice versa) inversion takes place when the attacking nucleophile is having the same priority (according to CIP rules) as the leaving group. Is my logic correct ?

| improve this question | | | | |
  • 1
    $\begingroup$ Hey there, you are correct. The assumption is that the nucleophile and leaving group have the same priority. $\endgroup$ – Michael Lautman Aug 26 '19 at 19:37
  • $\begingroup$ @MichaelLautman Thanks! $\endgroup$ – Deepam Sarmah Aug 27 '19 at 2:29

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.