# Exact weights for a chemical reaction og Silver and Nitric Acid [closed]

I'm an amateur analog photographer and want to react Nitric Acid (62%) and silver to Silver nitrate. Silver nitrate is the basis for almost all black and white photography.

I'm trying to figure out the correct ratio of silver to nitric acid. The reaction is $$\ce{3Ag(s) +4HNO3(aq) -> 3AgNO3(l) +NO(g) +2H2O (l)}$$

Can I calculate the ratio of silver to acid with the formula $$3 \times (\text{molar weight of Ag}) / 4 \times (\text{Molar weight of HNO3}) \times 0.62$$ ?

## closed as off-topic by Mithoron, Tyberius, Todd Minehardt, Mathew Mahindaratne, Buck ThornAug 18 at 9:21

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• This is just a bad idea. Molar proportion's your last concern with this reaction. – Mithoron Aug 16 at 18:16
• I'm perfectly aware of the reaction and it's bi product. Thanks for your concern! – Glenn Bech Aug 16 at 18:55

Therefore the mass ratio is: $$\frac{m(Ag)}{m(HNO3)} = \frac{3}{4}\frac{MM(Ag)}{MM(HNO3)} = 1.28$$