a. Reaction of $\ce{CO2}$ addition in water is as follows:
$\ce{CO2}$ + $\ce{H2O}$ $\ce{->}$ $\ce{H2CO3}$
b. Then, pH of $\ce{H2CO3}$ solution is increased to 12 by addition of 1M $\ce{NaOH}$.
So, the reaction would be:
$\ce{2NaOH(aq)}$ + $\ce{H2CO3(aq)}$ $\ce{->}$ $\ce{Na2CO3(aq)}$ + $\ce{2H2O}$
c. This new solution at pH 12 is added to $\ce{CaCl2}$ solution; the final reaction of the system would be:
( $\ce{Na2CO3(aq)}$ + $\ce{2H+}$ + $\ce{2OH-}$ ) + $\ce{CaCl2}$ $\ce{->}$ $\ce{CaCO3(s)}$ + $\ce{2 NaCl}$ + $\ce{2H2O}$
My questions are:
1. Is the final chemical reaction correct?
2. By setting the pH of step c equal to 12, which is ( $\ce{Na2CO3(aq)}$ + $\ce{2H+}$ + $\ce{2OH-}$ ), and addition of 50 ml of that to $\ce{CaCl2}$ solution, is it possible to make some sort of pH calculations?
$\ce{[H+]} = 10^{-12} M$
$\ce{[OH-]} = 10^{-2} M$
$\ce{[CO3]}$ = assuming 0.05 M in 50 ml
3. Overall, is it possible to do a numerical simulation (e.g., MATLAB) of change in the overall solution pH? OR, predict the final pH by calculations?
Thanks and Best Regards,