While finding bond moment of water we take the dipole moment of water as the vector sum of two O-H bonds and we calculate it to be 1.51D. But the lone pair is also present which affects the dipole moment. Why don't we include it in our calculation? Can you explain me?

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    $\begingroup$ This is nicely answered in wikipedia: en.wikipedia.org/wiki/Chemical_polarity . Just read down to, and including, the section on "Polar molecues" and look closely at the water molecule figure. There is nothing to worry about with lone pairs because it has already been factored in, as it were. In other words, oxygen is slightly negative, the two hydrogens are slightly positive and that gives the vector-summed dipole moment. $\endgroup$ – Ed V Aug 9 at 0:56

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