# Confused with 'discharge potential',preferential discharge theory [closed]

My book says that the ions which have least value of discharge potential are deposited first in the concerned electrode because the 'require' the least energy to do so.I am confused by 'require' , do ions upon discharging gain energy or lose energy , are ions in general not less stable than neutral counterparts?
further,suppose there are two contenders for the same electrode, say sodium ion and hydrogen ion during alkaline electrolysis of water , what is the need of adding the base , what actually is it doing and how does it improve electrolysis ?

• Add some context. This is not the standard terminology and your question is not clear. – M. Farooq Aug 8 at 2:59
• What context do you need ? It's a basic question and terminology used is what is given in my book , please elaborate – Nutan Prakash Aug 8 at 7:47

For a process to proceed spontaneously, the free energy change for the system (combined half-cells, say) has to be negative. The Nernst equation tells us that the free energy difference is given by $$\Delta G = -nFE$$ where E is the total cell potential. This value must be negative for the cell to discharge, which means E is required to be positive. This is what is meant by "require" (language is used in funny ways, ions don't really require anything). You have more choices than just discharging the cell: you can charge it (creating more of some of the ions). Unless the potential is such to cause discharge you may actually produce more of the ions that are disfavored under spontaneous (discharging) conditions.