Considering 1,3-butadiene (below) added to bromine water (considering it as $\ce{Br2(aq)}$): enter image description here

I've seen online that the products are 1,2-dibromobutene and 1,4 enter image description here

but what I don't understand is why wouldn't the other double bond undergo substitution again? They're on a carbon chain like normal so shouldn't they react with the bromine water too? Is something stopping it?

  • $\begingroup$ Given enough time and Br2, it would. $\endgroup$ Aug 7, 2019 at 12:45
  • $\begingroup$ Please don't use MathJax in titles. $\endgroup$
    – Zhe
    Aug 7, 2019 at 14:03

1 Answer 1


If reaction is carried out in 1:1 ratio of Br2 and 1,3 Butadiene, then the above two products will be formed. If more Br2 is taken, then surely 4 positions will be brominated.

  • $\begingroup$ Why answer a question that has already been answered by @Ivan Neretin in a comment? $\endgroup$
    – user55119
    Aug 7, 2019 at 14:09
  • 2
    $\begingroup$ @user55119 because a comment is not an answer. $\endgroup$ Aug 8, 2019 at 5:50

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