# Does 1,3-butadiene in bromine/water do addition twice?

Considering 1,3-butadiene (below) added to bromine water (considering it as $$\ce{Br2(aq)}$$):

I've seen online that the products are 1,2-dibromobutene and 1,4

but what I don't understand is why wouldn't the other double bond undergo substitution again? They're on a carbon chain like normal so shouldn't they react with the bromine water too? Is something stopping it?

• Given enough time and Br2, it would. – Ivan Neretin Aug 7 '19 at 12:45
• Please don't use MathJax in titles. – Zhe Aug 7 '19 at 14:03

## 1 Answer

If reaction is carried out in 1:1 ratio of Br2 and 1,3 Butadiene, then the above two products will be formed. If more Br2 is taken, then surely 4 positions will be brominated.

• Why answer a question that has already been answered by @Ivan Neretin in a comment? – user55119 Aug 7 '19 at 14:09
• @user55119 because a comment is not an answer. – Stian Yttervik Aug 8 '19 at 5:50