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I can figure out the value of 'n' in simple equations like Fe³⁺ + e⁻ → Fe²⁺ (which would be n=1 here.)

But in equations like 2Cu⁺→ Cu²⁺ + Cu, I can't figure it out. I assumed the value of n would be 2 here as two electrons are involved in the disproportionation reaction, but my book says n=1 here. Can anyone help me understand what is the value of 'n' in this equation? Thank you.

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  • $\begingroup$ One $\ce{Cu+}$ transfers an electron to the other, thus n=1. $\endgroup$ – Buck Thorn Aug 5 at 5:48
  • $\begingroup$ Why two electrons? You strip an electron from one Cu and give the same one electron to another Cu. $\endgroup$ – Ivan Neretin Aug 5 at 6:03
  • $\begingroup$ Oh, I understand where I was going wrong. I looked at the electrons on both sides of the equation. Thank you! $\endgroup$ – laksheya Aug 5 at 6:36