# Why methoxy group acts similar to trifluoromethyl in nucleophilic aromatic substitution

In an online test, the following question was asked:

The answer to this question was:

I totally agree with the answer, as $$\ce{OCH_3}$$ is an EDG, hence it will tend to form meta product in this reaction.

This article says that $$\ce{OCH_3}$$ behaves similar to $$\ce{CF_3}$$, but I can't figure out the possible reason. Any help is appreciated!