# Why is the peak-to-peak separation of cyclic voltammetry is 57 mV?

I'm studying CV, and I wonder if I can calculate the peak-to-peak separation of CV for a reversible redox system.

I found that the separation is 57 mV on my textbook, and my teacher taught me that is can be calculated theoretically using Nernst equation, but I think it is more complicated.

Is it easy enough (for sophomore) to calculate the value? And if it is, I want to know the way.

(Sorry for my poor English)

• The 57 mv is empirical and not related to the similar value from the Nernst equation. It arises from the numerical solution of the equations in the oxidation/reduction cycle. See Nicholson & Shain Anal. Chem. v36, p 706 1964 for the details of the calculation: not an easy read. In introduction is given by Mabbot J. Chem. Educ. v60, p697 1983 and Benschoten et al. ibid. v60 ,p772, 1983 – porphyrin Jul 26 '19 at 8:03