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How do I calculate the value of $i$ for 1.17% solution of $\ce{NaCl}$, if it is isotonic with 7.2% solution of glucose?

I actually do not know where to start in this question. is it possible to calculate the value of $i$ of $\ce{NaCl}$? is value of $i$ of glucose 1? I tried putting the osmotic pressures equal but the value of $i$ remains a suspense.

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  • $\begingroup$ Have a read through en.wikipedia.org/wiki/Van_%27t_Hoff_factor. Generally, in case of questions in books, it is assumed that the dissociation (or association) is complete, i.e. the NaCl exists only as $\ce{Na+}$ and $\ce{Cl-}$ in the solution. See if you get the solution. $\endgroup$ – Shoubhik Raj Maiti Jul 25 at 15:33
  • $\begingroup$ Consider $\pu{100 mL}$ solution of each. That means, the number of particles in $\pu{7.2 g}$ of glucose is equivalent to the number of particles in $\pu{1.17 g}$ of $\ce{NaCl}$. So, you can find the $i$ value of $\ce{NaCl}$ (you may need to assume $i=1$ for glucose). $\endgroup$ – Mathew Mahindaratne Jul 25 at 17:33

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