The Hinsberg test of $\ce{C5H14N2}$ compound produces a solid that is insoluble in 10% aq. $\ce{NaOH}.$ This solid derivative dissolves in 10% aq. $\ce{H2SO4}.$ Which of the following would best fit these facts?

enter image description here

I think b or d is the answer. The reason being it's insoluble in NaOH. That implies it should not contain 1 degree amine. Can anyone clarify any further?

  • 2
    $\begingroup$ Edit your question to explain why you think that and you will get answers. $\endgroup$ – Waylander Jul 20 at 8:18
  • $\begingroup$ Think about what base and acid solubility mean in the context of the question. $\endgroup$ – user55119 Jul 20 at 19:45

" compound produces a solid" indicates that a reaction has occured.(hence no 3° amine group(according to this)). Further this is insoluble in base so there is a 2° amine group.

"This solid dissolves in acid" directly implies that there is a 3° amine group.

Hence there is both 2° amine group as well as 3° amine group in the compound.

Hence option b is the correct answer.

References: 1. Solomon and Fryle Hinsberg Test

  • 1
    $\begingroup$ You might edit this answer to give detail on what the Hinsburg test is - I had never heard of it and had to look it up. $\endgroup$ – Waylander Jul 21 at 17:16

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.