0
$\begingroup$

For a gas having molar mass $M$, express specific heat at constant pressure in terms of heat capacity ratio.

My attempt:

using $ C_p - C_V = R $ and

$ \dfrac{C_p}{C_V} = \gamma $

$ C_p = \dfrac{R \gamma }{ \gamma - 1} $

But answer is $ C_p = \dfrac{R \gamma }{ M(\gamma - 1)} $

But from where this $M$ is coming from? Isn't specific heat independent of $M$?

|improve this question
$\endgroup$
  • $\begingroup$ I agree with your answer. $\endgroup$ – Chet Miller Jul 15 at 12:07
  • 1
    $\begingroup$ The answer you've got $\left(C_p=\dfrac{\gamma R}{\gamma-1}\right)$ has the SI units $\dfrac{J}{mol\cdot K}$. The provided answer is in $\dfrac{J}{g\cdot K}$. $\endgroup$ – Eashaan Godbole Jul 15 at 13:57

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.