Lewis structure of CN radical

I need to draw the Lewis formula for $$\ce{CN}$$. However, I am not sure how to draw the single free electron. My idea would be as follows:

$$\Large\ce{\llap{·}C#N\rlap{:}}$$

Does that make sense?

• This is an unusual question. Generally, we refer to cyanide as the $\ce{CN-}$ anion.
– Zhe
Jul 13, 2019 at 15:36
• That's what I thought too. I wasn't able to find anything related online. Jul 13, 2019 at 15:42
• @JohnyDow Well yes, there is indeed the cyanido radical, e.g. en.wikipedia.org/wiki/Cyano_radical Jul 13, 2019 at 17:07
• It has been made in the lab using $\ce{CH3CN + N2 -> CN + ...}$: articles.adsabs.harvard.edu//full/1995A%26A...304L...5K/… Jul 14, 2019 at 3:57