I was doing an electrochemical test (LPR) and Titanium Grade 5 produced by AM respassivated oxide layer faster than the specimen produced with traditional manufacturing under identical experimental conditions. I am wondering if this can be explained with 'porosity' and being exposed to more 'surface area' as a result?

Regardless of the the porosity level, will the SLM sample be air tight? Only then would my guess here be wrong. I am assuming that the layers below get exposed to oxygen as well which is why I see the plateau (a flatter curve) for SLMed specimen.

I am trying to find a reason for the slightly better performance of the same material from a corrosion point of view when submerged in a specific liquid.

Linear Polarization Resistance

  • $\begingroup$ Now which, SLM or AM? There can be all kinds of differences in surface structure or trace impurities. You've got their data sheets. $\endgroup$ – Karl Jul 12 '19 at 17:06
  • $\begingroup$ Alloyed titanium ( grade 5 = 6 Al, 4 V) has lower corrosion resistance in corrosive environments than the unalloyed grades. I never saw porosity on any titanium surface with a microscope. $\endgroup$ – blacksmith37 Jul 12 '19 at 21:03
  • $\begingroup$ AM = SLM for the purpose of this question. So please treat the AM as SLM in the graph. $\endgroup$ – Ahmad Shumayal Jul 13 '19 at 1:01

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