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What exactly is the significance of vapor pressure of a pure liquid(the one used in Raoult's Law)? Does it take into account the pressure exerted by the liquid on the walls of the container also or is it like the vapour pressure of the vapour which is attained through the equilibrium of the pure liquid?

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    $\begingroup$ The latter.$\,$ $\endgroup$ – Ivan Neretin Jul 11 at 20:12
  • $\begingroup$ It's the gas-pressure exerted by the molecules above the liquid, both on the liquid and on the container walls. $\endgroup$ – Comos Jul 12 at 16:21