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I have an anode & cathode, both of $100 \times \pu{100\\mm}$ size. The process requires $\pu{450\\A/m2}$ current density. How do I reverse calculate this? Do I use the total surface area of both Cathode and Anode or just Anode? Please help.

Thanks

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    $\begingroup$ You use the cross-section, just like it were a wire. $\endgroup$ – Karsten Theis Jul 11 at 13:34
  • $\begingroup$ Cross-section of both Anode and Cathode or just Anode? $\endgroup$ – Abhishek Sharma Jul 15 at 10:48
  • $\begingroup$ Just one. Like in a wire, you would measure the cross-sectional area once, not cut the wire into many piece and add up all the areas. See qph.fs.quoracdn.net/… $\endgroup$ – Karsten Theis Jul 15 at 14:54
  • $\begingroup$ Got it now. Thank you very much! Appreciate your help. $\endgroup$ – Abhishek Sharma Jul 15 at 15:54
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Do I use the total surface area of both Cathode and Anode or just Anode?

You use the cross-section, just like it were a wire.

Cross-section of both Anode and Cathode or just Anode?

Just one. Like in a wire, you would measure the cross-sectional area once, not cut the wire into many piece and add up all the areas.

https://qph.fs.quoracdn.net/main-qimg-aabadab6ad3379dffe9a3ecb89f466ee.webp

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    $\begingroup$ What about if anode & cathode are not of same dimensions? If I have an Aluminium sheet hardly 0.5mm thick and a Lead anode that is 3 mm thick, which cross section should I refer? $\endgroup$ – Abhishek Sharma Jul 16 at 5:26
  • $\begingroup$ If the electrodes have different areas exposed to the electrolyte, then the electrode with smaller area would have higher current density because the current density at an electrode is simply the current divided by the electrode’s area in contact with the electrolyte. $\endgroup$ – Ed V Aug 15 at 1:36

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