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Oxidation of 1,4-dimethylcyclohexane

I am having difficulty identifying the second product. Is it an ether, or a kind of epoxide? I am out of ideas on how to reach it.

However, I do have a general idea how to receive the first product, in the means of knowing that I have to first turn the 1,4-dimethylcyclohexane to an alkyl halide and then into an alkene and then an epoxide.

I would be grateful to receive an idea of how to start.

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    $\begingroup$ It's an ether, obviously. $\endgroup$ – Karl Jun 29 at 12:50
  • $\begingroup$ I would imagine you can access it via 1,4-dimethylcyclohea-1,4-diene $\endgroup$ – Waylander Jun 29 at 13:49
  • $\begingroup$ would it be logical that after reaching 1,4-dimethylcyclohea-1,4-diene doing the following: 1.hydration (to add OH next to Me) 2.hydrohalogenation( to add Br next to the opposite Me) 3.NaOH, H2O(to reduce OH to O-, thus allowing an intramolecular Sn2 reaction to occur). open to corrections. $\endgroup$ – baraah baryhe Jun 30 at 20:44

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