Why do processes like roasting and calcination require a temperature lower than the melting point? Since intermolecular forces are lower in a liquid won't it be easier to oxidise (roasting) / decompose (calcination) in this state than in a solid?

  • $\begingroup$ If you melt it ,the product is a complicated slag , rather than a low sulfur ore. $\endgroup$ Nov 27, 2019 at 16:36

1 Answer 1


Reason 1:

For example if you have an porous ore and you melt it, the surface area will decrease dramatically. If you just roast it, the surface area will stay about the same.

A higher surface area will aid calcination proceses as more oxygen gets into contact with the surface and will eventually react.

Reason 2:

A higher temperature means more energy to heat the ore and this means it costs more money.

Reason 3:

Some oxides will volatilize when temperature is high (e.g. litharge).


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.