Reaction between 1-methylcyclopentanol and potassium permanganate

In my basic organic chemistry class, I learned that only primary and secondary alcohols undergo oxidation (using $$\ce{KMnO4}$$).

However, what is the outcome of reacting tertiary alcohol (1-methylcyclopentanol) with a strong oxidant like $$\ce{KMnO4}$$ with no heat?

P.S. I am specifically interested to know what happens with no heat, because according to my minimal knowledge I know if heat was added then it is dehydration.

1. Abiko, A.; Roberts, J. C.; Takemasa, T.; Masamune, S. $$\ce{KMnO4}$$ Revisited: Oxidation of Aldehydes to Carboxylic Acids in the Tert-Butyl Alcohol - Aqueous $$\ce{NaH2PO4}$$ System. Tetrahedron Letters 1986, 27 (38), 4537–4540. https://doi.org/10/c3t9xj.