I had read that when an atom forms multiple bonds, it hybridises it's orbitals to minimise the repulsion and decrease the overall energy. But do the terminal atoms also exist in hybridised form?

E.g. in $\ce{CF4}$, are fluorine orbitals also $sp^3$ hybridised, or maybe has some other type of hybridization, or no hybridization at all?

Also in a molecules like say $\ce{HF}$, in this case is $\ce{F}$ hybridised or not?

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    $\begingroup$ Fluorine, not flourine.. $\endgroup$ – orthocresol Jun 25 '19 at 20:24
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    $\begingroup$ Hybridisation is a mathematical concept, you can use it or not, it does not make a difference. It cannot be measured. Please also note that atoms cannot be hybridised, only orbitals can. It is more than sloppy to say that 'F is hybridised'. $\endgroup$ – Martin - マーチン Jun 25 '19 at 21:04
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    $\begingroup$ @Martin-マーチン In other words, you mark «F is hybridised» with a F. $\endgroup$ – Buttonwood Jun 25 '19 at 21:30

No Fluorine is not hybridised because every atom of Fluorine in CF4 make one bond which is the typical according to the octet rule.

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