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Our instructor have us answer an isomerism problem of a crystal structure that has a form of $\ce{M(AB)2C2}$. I keep getting 9 isomers, which includes the optically inactive isomer, and my peers and I have different answers.

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  • $\begingroup$ I thought of several wrong ways to count isomers, and still failed to get 5. If you want us to tell which of your isomers is wrong or which one is missing, then we really need to know more. $\endgroup$ – Ivan Neretin Jun 19 at 11:10
  • $\begingroup$ After more fiddling I succeeded in getting 5. If your peers are getting more, they must be counting enantiomers. $\endgroup$ – Ivan Neretin Jun 19 at 11:23
  • $\begingroup$ Sorry, but I have noticed that 4 of my isomers have D and L forms so instead of 5, the isomers that I have is 9 including the one which is the optically inactive isomer. $\endgroup$ – Kent de los Reyes Jun 19 at 11:25
  • $\begingroup$ Great. (Or maybe not.) Now you are ahead of me, because I'm getting 8, of which two are optically inactive. $\endgroup$ – Ivan Neretin Jun 19 at 11:26
  • $\begingroup$ How did you form another optically inactive isomer? I am new to this topic that's why I can't trust my intuitions. $\endgroup$ – Kent de los Reyes Jun 19 at 11:31
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Referring to the replies of Mr. Ivan Neretin, complexes that has a form of M(AB)2C2 posses 8 stereoisomers, 2 of which are optically inactive. The other 6 isomers can be interchanged to their respective enantiomers.

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    $\begingroup$ Without some pictures this answer is hardly helpful for other people struggling with the question. It doesn't even specify the coordination of M. $\endgroup$ – Martin - マーチン Jun 19 at 13:40
  • $\begingroup$ I tried to at least put a picture of the complex for easier visualization but I failed to generate one. $\endgroup$ – Kent de los Reyes Jun 19 at 13:43
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    $\begingroup$ Do you have a pen and paper and a camera? This should work fine for starters, someone else might use the chance to produce higher quality images if necessary. $\endgroup$ – Martin - マーチン Jun 19 at 14:20
  • $\begingroup$ I don't have any gadgets with me except for this PC that I am using. $\endgroup$ – Kent de los Reyes Jun 19 at 14:23

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