Let's start with the reaction of 2-chlorobutane with ethanolic KOH.

Now, as per the stability of carbanions, 1-butene should be formed (due to higher stability of primary carbanion in its intermediate), but the product is 2-butene. Why is it so?

  • $\begingroup$ Have you studied the types of elimination reactions? It's all about Hofmann/Zaitsev products. $\endgroup$ – William R. Ebenezer Jun 18 '19 at 15:14
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    $\begingroup$ Carbonion is not a thing at all. There is a carbocation, and then there is a carbanion. Which one did you mean? $\endgroup$ – Ivan Neretin Jun 18 '19 at 15:35
  • $\begingroup$ Read your text. Is carbanion, atall an intermediate here?Under what conditions does it eliminate via carbanion? $\endgroup$ – Chakravarthy Kalyan Jun 18 '19 at 18:00
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    $\begingroup$ @Mithoron There is a 50% chance that your edit was misplaced. $\endgroup$ – Ivan Neretin Jun 18 '19 at 18:31
  • $\begingroup$ @IvanNeretin Not really, misspelling of one letter is much more probable then of 3. $\endgroup$ – Mithoron Jun 18 '19 at 18:37

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