I wanted to ask a question about metallic bond - band electron theory.

Consider the diagram of Sodium below:

enter image description here

Circled are orbitals both containing $2$ electrons each which combine using LCAO to give a set of bonding and antibonding electrons.

However, the $4$ electrons involved in this bonding appear to only give $3$ electrons in the bonding and antibonding MO's produced.

This confuses me. Surely using $4$ electrons, I expect all $4$ of these electrons to also be present in the rectangle drawn.

Why are there only 3 electrons shown? Is one electron being used for the next addition of AOs?

Any answers would be greatful!


From left to right, it shows 1, 2, 3, and 4 atoms of sodium, with a total of 1, 2, 3, and 4 valence electrons. So this diagram is different from others which have the uncombined AO's on the left and right, and the combined MO's in the middle. Here, we are adding more and more atoms to go from discreet energy levels (left 4 columns, up to four atoms) to a band structure (rightmost column, many atoms in bulk metal).

The only column that shows the AO is the left-most because for that one, there is only one atom, which means that there can't be any MOs.

Maybe this diagram makes more sense to you (the full and empty circles on the right show how the AO's are combined to make the bonding, non-bonding and antibonding MO's):

enter image description here

Source: http://xbeams.chem.yale.edu/~batista/vaa/nabands.gif

| improve this answer | |
  • $\begingroup$ Oh right! The above diagram makes sense. So, one question - why are there then the dotted lines between each MO following on from the leftmost AO towards the right? $\endgroup$ – vik1245 Jun 14 '19 at 1:04
  • $\begingroup$ @vik1245 You could imagine adding another and another AO one by one, or you could take the image I posted and rearrange it to get the other one. In any case, all the MO's are base on the one AO that is shown on the left. $\endgroup$ – Karsten Theis Jun 14 '19 at 1:06
  • $\begingroup$ Oh right so as I'm moving one to the right, I'm adding simply one AO to the right to get a new MO set, similar to what I can get if I simply splice your diagram and rearrange it to the image I posted? I think I get it then if I'm correct! Just confirm that please! $\endgroup$ – vik1245 Jun 14 '19 at 1:23
  • $\begingroup$ @vik1245 yup confirmed $\endgroup$ – Karsten Theis Jun 14 '19 at 2:32
  • $\begingroup$ Ticked! By the way in your diagram for $\ce{Na3}$ the middle energy set of orbitals, is that simply missing a black dot by mistake? $\endgroup$ – vik1245 Jun 14 '19 at 11:16

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.