I was asked to name the molecule below .
For the following molecule, since ether is a substituent here (keto is more prior group) my answer was:
My answer is wrong. The correct answer is
My point is, at C-3, ether is methoxy, but at 7 the same ether is OXA. Ether as substituent outside the bicyclo ring is alkoxy, but inside bicyclo compound it is OXA. My question is, why should ether O be named as OXA in a bicyclo ring?