EDIT
I am forced to reword my question about a chemical mixing ratio.
I have seen in Wikipedia that peroxide ($\ce{H2O2}$) and Acetic Acid can be mixed to Peracetic acid - this is an equilibrium.
I have also seen in Wikipedia that peracetic acid mixed with acetic acid will be explosive - in other words: If I don't get the mixing ratio just right then the "peracetic acid" will actually be "peracetic acid dissolved in acetic acid". I need to avoid this situation.
I have also read in Wikipedia that "thinning" the peracetic acid will shift the equilibrium and so this might end up in an explosive solution - I need to avoid this.
I have also seen at amazon.de that peressigsäure/alkohol is widely used as a disinfectant and I suppose the ratio of ethanol should be at 69% in order to kill most any microbes.
I need to mix a weak solution of $\ce{H2O2}$ and acetic acid and 69 % ethanol so that the peracetic equilibrium is held to be non explosive. And I also need to mix a more potent solution of $\ce{H2O2}$ and acetic acid and 69 % ethanol so that again, the peracetic equilibrium will fit and not be explosive.
As far as I understood it is not done by having the potent solution in the fridge at 0 degree Celsius and on demand simply thinning the potent solution to a weaker disinfectant - the peracetic equilibrium would then shift and it might become explosive.
Sorry, I am not really fit to calculate concentrations in Vals and Mols - but I could of course deal with any complex mathematical formula (on paper or on the calculator - or I could even code a small mixing calculator in java or c#).
So I would ask you to give me the right formula for my problem:
Component A = 12 % $\ce{H2O2}$
Component B = 20 % Acetic Acid
Component C = 98 % Ethanol
Component D = $\ce{H2O}$
AND I need 1 liter of mixture so that Alcohol appears with 69 VOL % and that peracetic acid appears with $x$ % ($x$ between 2 and 10) and no acetic acid will be in the mixture aside from the equilibrium.
I could then simply vary the $x$ (the conecntraction of peracetic acid) in the formula and mix as needed.
please, show me how to calculate the concentrations. thanks!