Formal Charge in Coordinate covalent bonds [closed]

I am in an honors chemistry course right now and I would like to know the formal charges of the atoms in CO, my confusion is that because the bond is partially coordinate covalent, are the bonded electrons still counted as #bonds/2 or should I count the number of electrons donated by each atom (making the formal charge 0 for both) Please help me understand and explain WHYnot just how. Thanks a lot.

closed as unclear what you're asking by Mithoron, Todd Minehardt, Jon Custer, user55119, M.A.R.Jun 6 at 15:13

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Carbon FC: $$\ce{(4 valence electrons on neutral atom) - (1*2e- from lone pair + 3*1e- from covalent bonds) = -1}$$
Oxygen FC: $$\ce{(6 valence electrons on neutral atom) - (1*2e- from lone pair + 3*1e- from covalent bonds) = +1}$$