I know that graphite and boron nitride are aromatic in nature.

In a similar way, can black phosphorous too exhibit aromaticity? Since it is essentially the same having 6 membered rings with lone pair of electrons and vacant d orbitals.

If not, then it would show some double bond character also, right?

  • 4
    $\begingroup$ According to: pubs.rsc.org/en/content/articlelanding/2018/NR/… [...] Despite the fact that BP does not show aromaticity or single atom thickness as graphene, it has something else in common with graphene as we report below [...] So, as to the aromatic character, it looks like it doesn't have it. Aside from that, it would be intuitive to guess it by looking at the shape of BP: it is not planar, which is a characteristic of "common" aromatic molecules: delocalization is not favoured $\endgroup$
    – user32223
    May 25, 2019 at 5:29
  • 2
    $\begingroup$ There. Are. No. Outer. d. Valence. Orbitals. Period! $\endgroup$ May 25, 2019 at 18:48


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