# Oxidative cleavage of styrene

I could understand that $$\ce{-CH=}$$ gets converted to $$\ce{-COOH}$$ and $$\ce{=CH2}$$ gets converted to $$\ce{CO2 + H2O}.$$

But I couldn't understand why the double bonds in benzene ring were not cleaved.

• They are if you heat it hard enough and long enough – Waylander May 21 at 13:11

Benzene ring is resonance stabilized and is highly stable . According to Huckel's Rule it has $$(4n+2)$$ $$e^-$$s (where $$n = 1$$), which makes this ring aromatic. This is the reason why $$\ce{KMnO4}$$ did not cleave the benzene ring.