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I could understand that $\ce{-CH=}$ gets converted to $\ce{-COOH}$ and $\ce{=CH2}$ gets converted to $\ce{CO2 + H2O}.$

But I couldn't understand why the double bonds in benzene ring were not cleaved.

Oxidative cleavage of styrene

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    $\begingroup$ They are if you heat it hard enough and long enough $\endgroup$ – Waylander May 21 at 13:11
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Benzene ring is resonance stabilized and is highly stable . According to Huckel's Rule it has $(4n+2)$ $e^-$s (where $n = 1$), which makes this ring aromatic. This is the reason why $\ce{KMnO4}$ did not cleave the benzene ring.

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  • $\begingroup$ If that is the case then how would we get ozololysed products of benzene? $\endgroup$ – user73099 May 21 at 16:15
  • $\begingroup$ I am still in High School and I haven't learnt a lot of Organic Chemistry yet. But maybe if you convert it into tertiary benzylic and then oxidise it , the ring will be destroyed. $\endgroup$ – RandomAspirant May 21 at 16:20
  • $\begingroup$ If you are in class 11 then you will learn ozonolysis reaction in few days then you would probably understand. $\endgroup$ – user73099 May 22 at 10:19
  • $\begingroup$ @ANBENZENE That's a different reagent. $\endgroup$ – Zhe Jun 20 at 17:20

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