# Oxidative cleavage of styrene

I could understand that $$\ce{-CH=}$$ gets converted to $$\ce{-COOH}$$ and $$\ce{=CH2}$$ gets converted to $$\ce{CO2 + H2O}.$$

But I couldn't understand why the double bonds in benzene ring were not cleaved.

• They are if you heat it hard enough and long enough – Waylander May 21 at 13:11

## 1 Answer

Benzene ring is resonance stabilized and is highly stable . According to Huckel's Rule it has $$(4n+2)$$ $$e^-$$s (where $$n = 1$$), which makes this ring aromatic. This is the reason why $$\ce{KMnO4}$$ did not cleave the benzene ring.

• If that is the case then how would we get ozololysed products of benzene? – user73099 May 21 at 16:15
• I am still in High School and I haven't learnt a lot of Organic Chemistry yet. But maybe if you convert it into tertiary benzylic and then oxidise it , the ring will be destroyed. – RandomAspirant May 21 at 16:20
• If you are in class 11 then you will learn ozonolysis reaction in few days then you would probably understand. – user73099 May 22 at 10:19
• @ANBENZENE That's a different reagent. – Zhe Jun 20 at 17:20