I am little bit confuse about relating the half life time period of a first order reaction something like

$$\ce{2A -> B + C}$$

Here the rate of reaction will be half of the rate at which $\ce{A}$ is used up.

$$\text{Rate of reaction} = k[\ce{A}]$$

$$\text{Rate of disapperance of}~\ce{A} = 2k[\ce{A}]$$

Integrating it half life will be $\displaystyle\frac{\ln 2}{2k}$. Am I wrong somewhere?

  • $\begingroup$ It is absolutely correct. $\endgroup$ – Harsh Wasnik May 12 '19 at 18:06
  • $\begingroup$ Is there something else you are confused about? Your math may be correct, but you seem to be implying that there is a problem with your answer. $\endgroup$ – Michael Lautman May 14 '19 at 20:27
  • $\begingroup$ Am I being obtuse here but $\ce{A+A\to \cdots}$ is a second order reaction, not a first order one which would be $\ce{A\to\cdots} $. You can also calculate the half life of a second order reaction. $\endgroup$ – porphyrin May 16 '19 at 18:33

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.