0
$\begingroup$

enter image description here

Is the answer A or B because C and D won't give me the rate constant?

$\endgroup$
  • $\begingroup$ C or D won't give you the rate constant. $\endgroup$ – Ivan Neretin May 6 at 6:00
  • $\begingroup$ C will only let you identify the order of reaction of X in this reaction and D will change the rate constant as the temperature change $\endgroup$ – Simon-Nail-It May 6 at 6:18
  • $\begingroup$ Tty to develop an straight equation equation from the rate equation $\endgroup$ – Simon-Nail-It May 6 at 6:29
1
$\begingroup$

From the graph it is clear that the reaction follows first order kinetics ($\ce{[X] = [X_0] e^{-kt}}$) where $ [X_0]$ is initial concentration. Taking $ln$ on both sides we get $\ce{ln[X] = ln[X_0] +(-kt)}$ So if you plot a graph between $ln[X]$ and $t$ then you have the magnitude of slope as k ie the equilibrium constant. So correct answer is A.

$\endgroup$

Not the answer you're looking for? Browse other questions tagged or ask your own question.