# Reaction of Br2/KOH with succinic anhydride

What products will be formed when $$\ce{Br2/KOH}$$ reacts with the following compound in water at room temperature?

Here is what I think is possible:

1. $$\ce{OH-}$$ will take up the acidic hydrogen.
2. $$\ce{OH-}$$ can attack the carbonyl group.
3. $$\ce{OBr-}$$ can attack the carbonyl group.
4. $$\ce{Br+}$$ can attack the lone pair of the doubly bonded oxygen and break the carbonyl bond.